Answer:
Step-by-step explanation:
[tex]x\geq 2x^2\\0\geq 2x^2-x\\2x^2-x\leq 0\\x^2-\frac{1}{2} x+(\frac{-1}{4} )^2\leq 0+(\frac{-1}{4} )^2\\(x-\frac{1}{4} )^2\leq (\frac{1}{16} )\\|x-\frac{1}{4} |\leq \frac{1}{4} \\|x-a|\leq b\\-b\leq x-a\leq b\\-\frac{1}{4} \leq x-\frac{1}{4} \leq \frac{1}{4} \\-\frac{1}{4} +\frac{1}{4} \leq x\leq \frac{1}{4} +\frac{1}{4} \\0\leq x\leq \frac{1+1}{4} \\0\leq x\leq \frac{1}{2}[/tex]
