Respuesta :

To find the mass in grams of \(2.00 \times 10^{23}\) molecules of Magnesium metal (Mg), we need to use Avogadro's number and the molar mass of Magnesium (Mg). Here are the steps we'll follow to solve the problem: **Step 1: Understand Avogadro's Number** Avogadro's number is a constant that represents the number of atoms or molecules in one mole of a substance. Avogadro's number is \(6.02214076 \times 10^{23}\) entities per mole. **Step 2: Calculate the Number of Moles of Magnesium** Since we have \(2.00 \times 10^{23}\) Magnesium molecules, we must first determine how many moles this number represents. We do this by dividing the number of molecules by Avogadro's number. \[ \text{Number of moles} = \frac{\text{Number of molecules}}{\text{Avogadro's number}} \] \[ \text{Number of moles (Mg)} = \frac{2.00 \times 10^{23}}{6.02214076 \times 10^{23}} \approx 0.3321 \text{ moles} \] **Step 3: Find the Molar Mass of Magnesium** The molar mass of an element is the mass of one mole of that element. The molar mass of Magnesium is \(24.305 \text{ g/mol}\). **Step 4: Calculate the Mass of Magnesium** To find the mass, multiply the number of moles by the molar mass of Magnesium. \[ \text{Mass} = \text{Number of moles} \times \text{Molar mass of Magnesium} \] \[ \text{Mass (Mg)} = 0.3321 \text{ moles} \times 24.305 \text{ g/mol} \approx 8.0719 \text{ grams} \] So, the mass in grams of \(2.00 \times 10^{23}\) molecules of Magnesium is approximately \(8.0719\) grams.
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