Mark is flying a kite to which the angle of elevation is 62 degrees. the string on the kite measures 55 meters long. How far is the kite above the ground?

Respuesta :

Answer:

Step-by-step explanation:

To find how far the kite is above the ground, we can use trigonometry, specifically the tangent function.

The tangent of an angle in a right triangle is equal to the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle.

In this case, the angle of elevation is 62 degrees, and the length of the string (hypotenuse) is 55 meters. Let

h represent the height above the ground.

So, we have:

tan

(

6

2

)

=

55

tan(62

)=

55

h

We can rearrange this equation to solve for

h:

=

55

×

tan

(

6

2

)

h=55×tan(62

)

Now, let's calculate it:

=

55

×

tan

(

6

2

)

h=55×tan(62

)

55

×

1.880726

h≈55×1.880726

103.44793

h≈103.44793

So, the kite is approximately

103.45

103.45 meters above the ground.

Answer:

103.44m

Step-by-step explanation:

The height of the kite above the ground can be calculated using the tangent function.

In this case, the angle of elevation is the angle between the ground and the string of the kite, which is 62 degrees. The string of the kite represents the hypotenuse of the right triangle, which is 55 meters long. We want to find the length of the opposite side, which represents the height of the kite above the ground.

The formula to calculate the height (h) is:

[tex]h=tan(angle)*hypotenuse[/tex]

Substituting the given values:

[tex]h=tan(62)*55=103.44m[/tex]

ACCESS MORE