A golf ball is hit at a cliff 150m away with an initial velocity of 70m/s at angle of 40° to the horizontal. A)How long will it take for the ball to hit the cliff B) At what height did the vall strike the cliff

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Answer:

Explanation:

A) R=(Vx) x (t)  
150= (70 x cos 40) x (t)
t=2.8 seconds
B)
y=(voy)(t)+1/2(ay)(t)^2
y= (70 x sin 40) (2.8)+1/2(-9.81)(2.8)^2
y= 87.5 m

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