Question

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An airplane takes off, levels off, and lands according to the diagram shown below.
All measurements listed are in kilometers. What is the horizontal distance from the plane's starting position to its finishing position? Round your answer to the nearest tenth of a kilometer.

Answer 1

The answer would be 13.3.

Use the Pythagorean theorem to find the other distances in the 5, 3, x triangle and the 7, 3, y triangle and add those two answers together plus 3 to get your answer.

Answer 2

The horizontal distance from the plane's starting position to its finishing position is 13.33 kilometers if the horizontal distance x is 4 km, and horizontal distance y is 6.33 km

What is a right-angle triangle?

It is defined as a triangle in which one angle is 90 degrees and the other two angles are acute angles. In a right-angled triangle, the name of the sides are hypotenuse, perpendicular, and base.

When the airplane takes off, the horizontal distance is x units, and it makes a right angle triangle(as shown in the picture) so applying Pythagoras theorem to find the value of x

5² = 3² + x²

25 = 9 + x²

25 - 9 = x²

x = 4 units

When, the airplane start to lands, the horizontal distance in this case is y units.

Again, applying Pythagoras theorem to find the value of y:

7² = 3² + y²

49 = 9 + y²

40 =  y²

y = 6.324 km ≈ 6.33 km

Total horizontal distance:

= x + 3 + y

= 4 + 3+ 6.33

= 13.33 km

Thus, the horizontal distance from the plane's starting position to its finishing position is 13.33 kilometers if the horizontal distance x is 4 km, and horizontal distance y is 6.33 km

Learn more about the right angle triangle here:

brainly.com/question/3770177

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