Question

Which table represents points in the graph of h(x)

Answer 1

hello : 
the third table because ; 
f(-6) = 2
f(1) =1
f(2) =0
f(3) =-1
f(6) =-2

Answer 2

Answer:

The table in the attached figure

Step-by-step explanation:

we have

$h(x)=\sqrt[3]{-x+2}$

Using a graphing tool

see the attached figure

The x-intercept of the function is the point $(2,0)$ (value of x when the value of the function is equal to zero)

The y-intercept of the function is the point $(0,1.26)$ (value of the function when the value of x is equal to zero)

therefore

First table

The y-intercept of the function is the point $(0,2)$

so

Is not represent the function h(x)

Second table

The y-intercept of the function is the point $(0,2)$

so

Is not represent the function h(x)

Third table

The x-intercept of the function is the point $(2,0)$

so

Could be represent the function h(x)

Fourth table

The x-intercept of the function is the point $(-2,0)$

so

Is not represent the function h(x)

Verify the third table

For $x=-6$

Find the value of y

substitute the value of x

$h(-6)=\sqrt[3]{-(-6)+2}=2$ -----> is ok

For $x=1$

Find the value of y

substitute the value of x

$h(1)=\sqrt[3]{-(1)+2}=1$ -----> is ok

For $x=3$

Find the value of y

substitute the value of x

$h(3)=\sqrt[3]{-(3)+2}=-1$ -----> is ok

For $x=10$

Find the value of y

substitute the value of x

$h(10)=\sqrt[3]{-(10)+2}=-2$ -----> is ok

The third  table represent the function h(x) ------> see the attached figure