Question

the length of a rectangle is 7 inches more than its width.if the perimeter of the rectangle is 66 inches,find its dimensions.

Answer 1

Perimeter = 2 times the width + 2 times the length
                = 2(w + 7) + 2w     where w = width

2(w + 7) + 2w = 66

4w + 14 = 66
4w = 66-14 = 52
w = 52/4 = 13

length = 13 + 7 = 20 

width = 13 and length = 20

Answer 2

p=66
L=7+w
2L+2W=p
2(7+w)+2w=66
14+2w+2w=66
4w=52
w=13
L=7+w
L=7+(13)
L=20 & w=13