Question

A high school drama club is selling tickets for the spring production. One day the president sold 12 adult tickets and 5 child tickets for a total of $169. The next day the president sold 22 adult tickets and 10 child tickets for a total of $314. Let a represent the cost of one adult ticket. Let c represent the cost of one child ticket. Which system of equations will solve for a and c?

Answer 1

Answer:

12a + 5c = 169

22a + 10c = 314  

Step-by-step explanation:

A high school drama club is selling tickets for the spring production.

One day president sold 12 adult tickets and 5 child tickets for a total of $169.

Let cost of adult ticket is a and for child ticket c

Therefore, equation will be

12a + 5c = 169

Next day the president sold 22 adult tickets and 10 child tickets. so equation will be

22a + 10c = 314  

so these are system of equations

Answer 2

In this exercise we have to use the knowledge of equations to assemble a system, in this way we have:

$12a + 5c = 169\\22a + 10c = 314$

Organizing the information given in the statement, we have that:

• A high school drama club is selling tickets for the spring production.

• One day president sold 12 adult tickets and 5 child tickets for a total of $169.

• Let cost of adult ticket is a and for child ticket c

With this information we can call set up the equation as:

$12a + 5c = 169\\22a + 10c = 314$

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