Respuesta :
We know the equation of latent heat:
Q = mL
(Energy = mass * latent heat)
Therefore, this problem is a regular application of this:
Q = 25.4 * 61.7
Q = 1567,18
With the 3 digits:
Q = 1570 J
Q = mL
(Energy = mass * latent heat)
Therefore, this problem is a regular application of this:
Q = 25.4 * 61.7
Q = 1567,18
With the 3 digits:
Q = 1570 J
Answer : The energy needed to melt 25.4 grams of [tex]I_2[/tex] is, [tex]1.57\times 10^{3}J[/tex]
Explanation : Given,
Mass of [tex]I_2[/tex] = 25.4 g
[tex]H_{fus}[/tex] = 61.7 J/g
As, 1 gram of [tex]I_2[/tex] melt to needed energy = 61.7 J
So, 25.4 gram of [tex]I_2[/tex] melt to needed energy = [tex]25.4\times 61.7=1567.18J=1.57\times 10^{3}J[/tex]
Therefore, the energy needed to melt 25.4 grams of [tex]I_2[/tex] is, [tex]1.57\times 10^{3}J[/tex]