Find the probability of choosing a letter other than the letter M from a bag that contains the sixteen letters of the name HERMANN MINKOWSKI. Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth

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Answer:

You count the number of letters that are not 'M' which is 15, then divide it by the total number of letters, which is 16.

So, the probability of choosing a letter other than 'M' is 15/16 or approximately 0.9375.

Answer:

The probability of choosing a letter other than the letter M = 7/8

Step-by-step explanation:

Let P(M) = probability of choosing the letter M
Then P(M') is the probability of not choosing M

P( M') = 1 - P(M) since M and M' are complementary events - either you pick the letter M or some other letter

There are a total of 16 letters out of which 2 letters are the letter M

P(M) = 2/16 = 1/8

P(M') = 1 - 1/8 = 7/8

The probability of choosing a letter other than the letter M = 7/8

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