Question

pls help we need to factor to get the answer btw

Answer 1

Answer: 0.55555555555, I think.

Answer 2

Answer:

$\boxed{\dfrac{5}{9}}$

Step-by-step explanation:

Given expression is
$\dfrac{69}{71} \cdot \dfrac{5}{9} + \dfrac{3}{71}\cdot \dfrac{5}{9} - \dfrac{5}{9}\cdot \dfrac{1}{71}$

• 5/9 is a common factor so factor outside the expression to get:
  $\dfrac{5}{9}\left(\dfrac{69}{71} \cdot 1+ \dfrac{3}{71} \cdot 1- 1. \dfrac{1}{71}\right)\\\\=\dfrac{5}{9}\left(\dfrac{69}{71}+ \dfrac{3}{71} - \dfrac{1}{71}\right)$
• 71 on the denominator is common to all three expressions in the parenthesis; that means $\dfrac{1}{71}$ can be factored out:
  $\dfrac{5}{9}\left(\dfrac{69}{71} \cdot 1+ \dfrac{3}{71} \cdot 1- 1. \dfrac{1}{71}\right)\\\\=\dfrac{5}{9}\left(\dfrac{69}{71}+ \dfrac{3}{71} - \dfrac{1}{71}\right)$
• Since the expression in parenthesis has the common denominator 71 we can simply calculate the numerator addition/subtraction and use 71 as the denominator of the result
  $\dfrac{5}{9}\left(\dfrac{69}{71}+ \dfrac{3}{71} - \dfrac{1}{71}\right)\\\\= \dfrac{5}{9}\left(\dfrac{69 + 3 - 1}{71}\right)\\\\= \dfrac{5}{9}\left(\dfrac{71}{71}\right)\\\\= \dfrac{5}{9}\left(1\right)\\\\= \dfrac{5}{9}\\\\\text{Answer: \boxed{\dfrac{5}{9}}}$