Triangle DEF is a right triangle with a right angle at vertex F. Side DF has a length of 9 inches and side FE has a length of 12 inches. What is the length, in inches, of side DE?

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Answer:

[tex]15[/tex] inches.

Step-by-step explanation:

In a right triangle, the length of the hypotenuse can be found from that of the other two sides using the Pythagorean Theorem.

In this question:

  • Side [tex]({\rm DF}) = 9[/tex] inches (adjacent to the right angle).
  • Side [tex]({\rm FE}) = 12[/tex] inches (adjacent to the right angle).
  • The length of side [tex]({\rm DE})[/tex] (hypotenuse, opposite the right angle) needs to be found.

By the Pythagorean Theorem:

[tex]\begin{aligned} \underbrace{({\rm DE})}_{\text{hypotenuse}} &= \underbrace{\sqrt{({\rm DF})^{2} + ({\rm FE})^{2}}}_{\text{adjacent to right angle}} \\ &= \sqrt{9^{2} + 12^{2}} \\ &= 15 \end{aligned}[/tex].

In other words, the length of the hypotenuse [tex]({\rm DE})[/tex] would be [tex]15[/tex] inches.

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