Question

. For the circuit shown in Figure 4, determine the value of V1. If the total circuit resistance is 3602, determine the supply current and the value of resistors R1, R2 and R3. R₁₁ R₂ R3 V₁ 5V 3V 18 V​

Answer 1

Answer:

V1 = 10V

The supply current = 0.5A.

R1 = 20 ohms

R2 = 10 ohms

R3 = 6 ohms

Explanation:

V2 = 5V, V3 = 3V, V1 = ?

Since the resistors are connected in series,

V1 + V2 + V3 = 18V

V1 + 5 + 3 = 18, V1 = 18 - 10 = 8

V1 = 8V.

From Ohm's law,

Vtotal = I total x Rtotal

18 = I total + 36

Itotal = 18/36 = 1/2A = 0.5A

The current supply = 0.5A.

Since the resistors are arranged in series, same current passes through them all. Therefore,

R1 = V1/0.5 = 10/0.5 = 20 ohms

R2 = V2/0.5 = 5/0.5 = 10 ohms

R3 = V3/0.5 = 3/0.5 = 6 ohms