f'(π/6) = √3/2
1. Differentiate f(x) = sin(x) to get f'(x) = cos(x).
2. Substitute x = π/6 into f'(x) to evaluate f'(π/6).
3. Use the value of cos(π/6) which is √3/2 to get f'(π/6) = √3/2.
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