Answer:
x can have any value and the equations will work.
The y- y-values will depend on the x chosen.
Step-by-step explanation:
2x+8y=6 and −5x−20y=−15
There are different options available to solve the equations.
→ elimination
→ substitution → single variable
→ equating
→ matrices
→ graphically
To be able to use substitution, a single variable in one of the equations is a useful indicator
2x+8y=6 ÷2→ x+4y=3
Make x the subject of the equation:
x=3−4y
Replace x in the second equation by (3−4y)
−5x−20y=−15
××↓
−5(3−4y)−20y=−15
−15+20y−20y=−15
−15=−15
x can have any value