Question

A rectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 192 ​yards, what are its​ dimensions

Answer 1

P = 2(L + W)
P = 192
L = 2W

192 = 2(2W + W)
192 = 2(3W)
192 = 6W
192/6 = W
32 = W <=== the width is 32 yards

L = 2W
L = 2(32)
L = 64 <=== the length is 64 yards