Question

Given (x – 7)2 = 36, select the values of x.



x = 13



x = 1



x = –29



x = 42

Answer 1

The answer is below:
13 & 1

Answer 2

we have

$(x-7)^{2} =36$

square root on both sides

$(x-7)=(+/-)\sqrt{36}$

$(x-7)=(+/-)6$

$x=(+/-)6+7$

$x1=6+7=13$

$x2=-6+7=1$

therefore

the answer is

$x1=13$

$x2=1$