Question

50 POINTS! PLEASE HELP!
Solve the equation with parentheses and variables on both sides of the equal sign.
5(x-4)+3x-9x=6-(2x+5)+8x
Part1: Use the distributive property to remove the parentheses.
Part2: Collect any like terms on both sides of the equation.
Part3: Bring all variable terms to one side of the equation. (Hint: Add x to both sides)
Part4: Bring all constant terms to one side. A constant term is a number without a variable. (Hint: Subtract 1 from both sides.)
Part5: Now solve the one-step equation. Show your work.

Answer 1

Step 1. Simplify brackets

$5(x-4)+3x-9x=6-2x-5+8x$

Step 2. Simplify $5(x-4)+3x-9x$ to $5(x-4)-6x$

$5(x-4)-6x=6-2x-5+8x$

Step 3. Simplify $6-2x-5+8x$ to $1+6x$

$5(x-4)-6x=1+6x$

Step 4. Expand

$5x-20-6x=1+6x$

Step 5. Simplify $5x-20-6x$ to $-x-20$

$-x-20=1+6x$

Step 6. Add $x$ to both sides

$-20=1+6x+x$

Step 7. Simplify $1+6x+x$ to $1+7x$

$-20=1+7x$

Step 8. Subtract $1$ from both sides

$-20-1=7x$

Step 9. Simplify $-20-1$ to $-21$

$-21=7x$

Step 10. Divide both sides by $7$

$- \frac{21}{7} =x$

Step 11. Simplify $\frac{21}{7}$ to $3$

$-3=x$

Step 12. Switch sides

$x=-3$

Done! :)

Answer 2

$Answer:$

$x = -3$

$Step-by-step~explanation:$

$5x-20+3x-9x=6-(2x+5)+8x$

$8x-20-9x=6-(2x+5)+8x$

$-x-20=6-(2x+5)+8x$

$-x-20=6-2x-5+8x$

$-x-20=1-2x+8x$

$-x-20=1+6x$

$-x-20-6x=1$

$-7x-20=1$

$-7x=1+20$

$-7x=21$

$\frac{21}{-7}$

$-3$