Respuesta :
(y + 3)(y^2 - 3y + 9) =
y(y^2 - 3y + 9) + 3(y^2 - 3y + 9) =
y^3 - 3y^2 + 9y + 3y^2 - 9y + 27 =
y^3 + 27 <==
y(y^2 - 3y + 9) + 3(y^2 - 3y + 9) =
y^3 - 3y^2 + 9y + 3y^2 - 9y + 27 =
y^3 + 27 <==
Answer:
option (1) is correct.
the product of the binomial by the trinomial is [tex]y^3+27[/tex].
Step-by-step explanation:
Binomial is the term having two different term and trinomial having three different terms.
Here, Binomial is [tex]y+3[/tex] and trinomial is [tex]y^2-3y+9[/tex]
We have find the product of the binomial by the trinomial.
[tex](y+3)(y^2-3y+9)[/tex]
Multiply each term of binomial with trinomial,
[tex]\Rightarrow y(y^2-3y+9)+3(y^2-3y+9)[/tex]
[tex]\Rightarrow y^3-3y^2+9y+3y^2-9y+27[/tex]
Combining like term, we get,
[tex]\Rightarrow y^3+(3-3)y^2+(9-9)y+27[/tex]
[tex]\Rightarrow y^3+27[/tex]
Thus, the product of the binomial by the trinomial is [tex]y^3+27[/tex].
Hence, option (1) is correct.