Question

WILL MARK BRAINLIEST PLS HELP!!!

Answer 1

Answer:

• For y = 0, x = 3(0)^2 = 0
• For y = 1, x = 3(1)^2 = 3
• For y = -1, x = 3(-1)^2 = 3
• For y = 2, x = 3(2)^2 = 12
• For y = -2, x = 3(-2)^2 = 12.

So, the solutions to the equation x = 3y^2 in integers are (x, y) = (0, 0), (3, 1), (3, -1), (12, 2), (12, -2).

- Q.E.

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