Answer:
See below
Step-by-step explanation:
To express the trigonometric functions of angles [tex] \alpha [/tex] and [tex] \beta [/tex] in terms of the given sides [tex] x [/tex], [tex] y [/tex], and [tex] z [/tex], we can use the definitions of sine, cosine, and tangent:
a) For angle [tex] \alpha [/tex]:
[tex] \sin \alpha =\dfrac{\textsf{opposite}}{\textsf{hypotenuse}} \\\\ = \dfrac{x}{z}[/tex]
[tex] \cos \alpha = \dfrac{\textsf{adjacent}}{\textsf{hypotenuse}} \\\\\ = \dfrac{y}{z}[/tex]
[tex] \tan \alpha =\dfrac{\textsf{opposite}}{\textsf{adjacent}} \\\\ = \dfrac{x}{y}[/tex]
b) For angle [tex] \beta [/tex]:
[tex] \sin \alpha =\dfrac{\textsf{opposite}}{\textsf{hypotenuse}} \\\\ = \dfrac{y}{z}[/tex]
[tex] \cos \alpha = \dfrac{\textsf{adjacent}}{\textsf{hypotenuse}} \\\\\ = \dfrac{x}{z}[/tex]
[tex] \tan \alpha =\dfrac{\textsf{opposite}}{\textsf{adjacent}} \\\\ = \dfrac{y}{x}[/tex]
c)
Now, let's determine whether each of the given statements is true or false:
1) [tex] \sin \alpha = \cos \beta [/tex]:
[tex] \sin \alpha = \dfrac{x}{z} [/tex]
[tex] \cos \beta = \dfrac{x}{z} [/tex]
Since both expressions are equal, this statement is true.
2) [tex] \tan \alpha = \cot \beta [/tex]:
[tex] \tan \alpha = \dfrac{x}{y} [/tex]
[tex] \cot \beta = \dfrac{1}{\tan \beta} = \dfrac{1}{\dfrac{y}{x}} = \dfrac{x}{y} [/tex]
Since both expressions are equal, this statement is true.
3) [tex] \sec \alpha = \csc \beta [/tex]:
[tex] \sec \alpha = \dfrac{1}{\cos \alpha} = \dfrac{1}{\dfrac{y}{z}} = \dfrac{z}{y} [/tex]
[tex] \csc \beta = \dfrac{1}{\sin \beta} = \dfrac{1}{\dfrac{y}{z}} = \dfrac{z}{y} [/tex]
Since both expressions are equal, this statement is true.
Therefore, all three statements are true.