An electrochemical cell is constructed to determine the concentration of Cu+ ions. One half-cell consists of a copper electrode in a 1.00 M copper(I) nitrate. The other half-cell consists of a copper electrode in a saturated solution of copper(I) chloride. The measured cell potential is 0.175 V. Determine the concentration of Cu+ ions in the saturated copper(I) chloride solution.

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Answer:

To determine the concentration of Cu+ ions in the saturated copper(I) chloride solution, we can follow these steps:

1. Write the balanced redox equation for the electrochemical cell:

Cu+ (from copper(I) nitrate) + e- -> Cu (copper solid)

Cu+ (from copper(I) chloride) + e- -> Cu (copper solid)

2. Calculate the standard cell potential (E°cell) using the standard reduction potentials for the half-reactions involved. The standard reduction potential for Cu+ + e- -> Cu is 0.52 V.

3. Use the Nernst equation to relate the measured cell potential (Ecell) to the standard cell potential (E°cell) and the concentrations of the Cu+ ions in the two half-cells:

Ecell = E°cell - (0.0592/n) * log(Q)

where n is the number of electrons transferred (1 in this case), and Q is the reaction quotient.

4. Substitute the given values into the Nernst equation:

0.175 V = 0.52 V - (0.0592/1) * log([Cu+ in CuCl]/[Cu+ in CuNO3])

5. Rearrange the equation to solve for [Cu+ in CuCl]:

[Cu+ in CuCl] = 10^((E°cell - Ecell) / (0.0592)) * [Cu+ in CuNO3]

6. Plug in the known values:

[Cu+ in CuCl] = 10^((0.52 V - 0.175 V) / 0.0592) * 1.00 M

7. Calculate the concentration of Cu+ ions in the saturated copper(I) chloride solution using the above formula.

By following these steps and calculations, you can determine the concentration of Cu+ ions in the saturated copper(I) chloride solution based on the given information about the electrochemical cell and the measured cell potential.

Explanation:

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