To find the molar mass of Pb3(PO4)4, you need to consider the individual atomic masses of each element in the compound and then sum them up according to their respective subscripts:
1. **Determine the atomic masses**:
- The atomic mass of lead (Pb) is approximately 207.2 g/mol.
- The atomic mass of phosphorus (P) is approximately 30.97 g/mol.
- The atomic mass of oxygen (O) is approximately 16.00 g/mol.
2. **Calculate the molar mass**:
- For Pb3(PO4)4, there are three lead atoms (Pb), four phosphate groups (PO4), and a total of 16 oxygen atoms (4 oxygen atoms in each phosphate group).
- Molar mass = (3 * atomic mass of Pb) + (4 * (atomic mass of P + 4 * atomic mass of O))
- Molar mass = (3 * 207.2) + (4 * (30.97 + 4 * 16.00))
- Molar mass = 621.6 + 4 * (30.97 + 64.00)
- Molar mass = 621.6 + 4 * 94.97
- Molar mass = 621.6 + 379.88
- Molar mass = 1001.48 g/mol.
Therefore, the molar mass of Pb3(PO4)4 is approximately 1001.48 g/mol.
