Answer:
The acceleration of the car was -4.4545 m/sec² where the negative sign indicates deceleration (decrease in acceleration)
Explanation:
To answer this question, we will use the following equation of motion:
v² = u² + 2as
where:
v is the final velocity = 0 m/sec (car became at rest)
u is the initial velocity = 28 m/sec
a is the acceleration we want to find
s is the distance covered = 88 m
Substitute with the givens in the equation to get "a" as follows:
v² = u² + 2as
0 = (28)² + 2(a)(88)
0 = 784 + 176a
176a = -784
[tex] a = \frac{-784}{176} [/tex] = -4.4545 m/sec²
Hope this helps :)
