Question

Christian sold tickets to the game. good seats for $5 each in poor seats cost $2 each. 210 people attended and pay $660. write a system of linear equations that can be used to find how many good seats and poor seats were sold. how many of each type of seat were sold?

Answer 1

Answer:

5x+5y = total amount of seats???

Step-by-step explanation:

Answer 2

Answer:

130 poor seats and 80 good seats

Step-by-step explanation:

G = good seats

P = poor seats

Let's begin with the amount of money:

5$ for good seats and 2$ for poor seats and the total is 660$

so the equation will be: 5h + 2p = 660

Next, the number of people that will attend:

The total number of people attending equals the number of people in good seats and poor seats

So the equation will be: h + p = 210

Rewrite the second equation and put it into the first equation

h + p = 210 -> h = 210 - p

5( 210 - p ) +2p = 660

Solving for P:

1050 - 5p +2p = 660

1050 - 3p = 660

1050 - 660 = 3p

390 = 3p

130 = p

Therefore: 130 poor seats were sold.

Solving for G, just plug it back into either equation and solve:

5h + 2p = 660

5h + 2(130) = 660

5h = 660 - 260

5h = 400

h = 80

Therefore: 80 good seats were sold.