If the probability that the Islanders will beat the Rangers in a game is 37%, what is the probability that the Islanders will win exactly six out of six games in a series against the Rangers? Round your answer to the nearest thousandth

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Answer:

0.0021 or 0.21%

Step-by-step explanation:

To find the probability that the Islanders will win exactly six out of six games in a series against the Rangers, we can use the binomial probability formula:

P(X = k) = (n choose k) * p^k * (1-p)^(n-k)

Where:

- n = total number of games in the series (6 games)

- k = number of games the Islanders win (6 games)

- p = probability that the Islanders will win a game (0.37)

- (n choose k) = n! / k!(n-k)!

Plugging in the values:

P(X = 6) = (6 choose 6) * 0.37^6 * (1-0.37)^(6-6)

P(X = 6) = 1 * 0.37^6 * (1-0.37)^0

P(X = 6) = 0.37^6

P(X = 6) ≈ 0.0021

Therefore, the probability that the Islanders will win exactly six out of six games in a series against the Rangers is approximately 0.0021, or 0.21% when rounded to the nearest thousandth.

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