Answer:
0.020925
Explanation:
to calculate the number of moles of potassium bromide present in 0.045 L of 0.465 M solution, you can use the formula:
\[ \text{moles} = \text{volume (L)} \times \text{molarity (M)} \]
1. First, plug in the values into the formula:
- Volume = 0.045 L
- Molarity = 0.465 M
2. Multiply the volume by the molarity:
\[ \text{moles} = 0.045 \, \text{L} \times 0.465 \, \text{M} \]
3. Calculate the moles of potassium bromide:
\[ \text{moles} = 0.045 \times 0.465 = 0.020925 \, \text{moles} \]
Therefore, there are 0.020925 moles of potassium bromide present in 0.045 L of 0.465 M solution.
