Question

Deangelo has $7 worth of dimes and quarters in a jar. He has 7 more quarters than dimes.
How many of each coin does he have?

Answer 1

d=number of dimes
q=number of quarters

let's count everything in cents
dimes are worth 10 cents
quarters are worth 25 cents

10d+25q=700
divide both sides by 5
2d+5q=140


he has 7 more quarters than dimes
q=7+d
subsitute 7+d for q in other equation

2d+5q=140
2d+5(7+d)=140
2d+35+5d=140
7d+35=140
minus 35 both sides
7d=105
divide both sides by 7
d=15

sub back

q=7+d
q=7+15
q=22


22 quarters and 15 dimes

Answer 2

Deangelo has 15 dimes and 22 quarters

Hope this helps