Question

how to use the zero product property and factoring solve for X

Answer 1

Using the zero product property you can set each expression equal to 0 (or factor for some of them)
All you have to do is set them equal to zero and simplify to solve for x

a. (x+13)=0
x= -13
(x-7)=0
x=7

b. (2x+3)=0
x=-3/2
(3x-7)=0
x=7/3

c. x=0
(x-3)=0
x=3

d. $x^{2} -5x=0$ needs to be factored 
factor out an x to get:
x(x-5) and set each equal to 0
x = 0       
(x-5)=0 
x=5

e. $x^{2} -2x-35=0$ also needs to be factored
(x-7)(x+5)=0
(x-7)=0       (x+5)=0
x=7   x=-5

f. $3x^{2} +14x-5=0$
Also needs to be factored using the ac method:
$3 x^{2} +15x-x-5$
$3 x^{2} (x+5)-1(x+5)$
$(3x-1)(x+5)=0$
(3x-1)=0
x=1/3
(x+5)=0
x=-5

I hope this helps! (if so, give brainliest please!!)