Respuesta :
3x+1=-7
3x = -8 subtract 1 from both sides to separate the x
X= -8/3 divide both sides by 3 to find the value of x
6(-8/3) + 5 replace x with the value of x that you found in the other equation
16 + 5 multiply 6 * (-8/3)
21 add 16+5
3x = -8 subtract 1 from both sides to separate the x
X= -8/3 divide both sides by 3 to find the value of x
6(-8/3) + 5 replace x with the value of x that you found in the other equation
16 + 5 multiply 6 * (-8/3)
21 add 16+5
remember, you can do anything to an equation as long as you do it to both sides
3x+1=-7
minus 1 both sides
3x+1-1=-7-1
3x+0=-8
3x=-8
divide both sides by 3
[tex]\frac{3x}{3}=\frac{-8}{3}[/tex]
[tex]\frac{3}{3}x=\frac{-8}{3}[/tex]
[tex]1x=\frac{-8}{3}[/tex]
[tex]x=\frac{-8}{3}[/tex]
ok for 6x+5
6x+5
[tex]6(\frac{-8}{3})+5=[/tex]
[tex]\frac{-48}{3}+5=[/tex]
[tex]-16+5=[/tex]
[tex]-11[/tex]
[tex]x=\frac{-8}{3}[/tex] and [tex]6x+5=-11 \space\ for \space\ x=\frac{-8}{3}[/tex]
3x+1=-7
minus 1 both sides
3x+1-1=-7-1
3x+0=-8
3x=-8
divide both sides by 3
[tex]\frac{3x}{3}=\frac{-8}{3}[/tex]
[tex]\frac{3}{3}x=\frac{-8}{3}[/tex]
[tex]1x=\frac{-8}{3}[/tex]
[tex]x=\frac{-8}{3}[/tex]
ok for 6x+5
6x+5
[tex]6(\frac{-8}{3})+5=[/tex]
[tex]\frac{-48}{3}+5=[/tex]
[tex]-16+5=[/tex]
[tex]-11[/tex]
[tex]x=\frac{-8}{3}[/tex] and [tex]6x+5=-11 \space\ for \space\ x=\frac{-8}{3}[/tex]
