Question

The radius of the base of a cylinder is 28 cm and its height is 48 cm. Find the surface area of the cylinder in terms of π.

Answer 1

area of the bases


2πr2=2π∗784=1568π


circumference of base


2πr=56π


extension of the height


2πr∗h=56π∗48=2688π


bases plus none base surface is total surface


1568π+2688π=4256π

Answer 2

Answer:  The required surface area of the given cylinder is 4256π cm².

Step-by-step explanation:  Given that the radius of the base of a cylinder is 28 cm and its height is 48 cm.

We are to find the surface area of the cylinder in terms of π.

We know that

the SURFACE AREA of a cylinder with base radius r units and height h units is given by

$S.A.=2\pi r(r+h).$

For the given cylinder, we have

r = 28 cm   and   h = 48 cm.

Therefore, the surface area of the cylinder will be

$S.A.\\\\=2\pi r(r+h)\\\\=2\pi \times28(28+48)\\\\=56\pi\times 76\\\\=4256\pi~\textup{cm}^2.$

Thus, the required surface area of the given cylinder is 4256π cm².