31-08-2017
Mathematics

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Evaluate ƒ(x) = –x2 + 1 for x = –3.

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acevedobobbyovg730 acevedobobbyovg730

31-08-2017

f(x)= 7
you take -x and replace it with -3 witch turns it to a positive then multiply 2 times 3 then add one There for x is 7

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nicolina nicolina

31-08-2017

ƒ(x) = -(-3)^2 + 1
ƒ(x) = - 9 + 1
ƒ(x) = - 8

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