What is the approximate value of q in the equation below.

q+logbase2 6=2q+2

-1.613
-1.522
0.585
3.079


I have chosen -1.613 but it was wrong apparently.

Respuesta :

The answer is 0.585.
q+logbase2 6=2q+2
The binary logarithm of 6 is 2.585 .
2q - q = 2.585 - 2
q = 0.585

The correct option is:   0.585

Explanation

Given equation is:    [tex]q+log_{2}6 = 2q+2[/tex]

First we will subtract [tex]q[/tex] from both sides and also subtract 2 from both sides. So, we will get.........

[tex]q+log_{2}6-q-2=2q+2-q-2\\ \\ log_{2}6 -2= q[/tex]

Now, the value of [tex]log_{2}6 = 2.58496.....[/tex]

So,  [tex]q= 2.58496.... -2 = 0.58496.... \approx 0.585[/tex]

Thus, the approximate value of  [tex]q[/tex] will be 0.585

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