Question

Avery was playing a game with 2 standard number cubes (dice). What is the probability Avery will roll a three on the first number cube and a number less than three on the second number cube?

Answer 1

Answer:

1/18

Step-by-step explanation:

The two events are independent, so the overall probability is the product of the individual probabilities.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

The roll of 1 die has a total of 6 possible outcomes: 1, 2, 3, 4, 5, 6

First die: roll a 3.

There is 1 desired outcome.

p(roll a 3) = 1/6

Second die: roll a number less than 3.

There are 2 desired outcomes, rolling a 1 or a 2.

p(roll less than 3) = 2/6 = 1/3

p(roll a 3 then roll number less than 3) = 1/6 × 1/3 = 1/18