Suppose a ball is thrown upward at a velocity of 40 ft/sec from a cliff that is 100 ft. above a dry riverbed. Write an equation for the height of the ball (h) after (t) seconds.

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Answer:

Step-by-step explanation:

When a ball is thrown upward, its height can be determined using the following equation:

h(t) = h0 + v0t - 16t^2

Where:

- h(t) represents the height of the ball at time t,

- h0 is the initial height at t = 0 (in this case, the cliff's height of 100 ft),

- v0 is the initial velocity of the ball (in this case, 40 ft/sec),

- t is the time in seconds.

Substitute the given values into the equation:

h(t) = 100 + 40t - 16t^2

So, the equation for the height of the ball after t seconds is h(t) = 100 + 40t - 16t^2.

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