Question

I need help with my homework it is too hard

Answer 1

Answer:

$\text{2 math books and 6 english books}$

Step-by-step explanation:

$\text{Let's assume that he bought }x\text{ math books and }y\text{ english books.}$

$\text{Given, }\\\text{Total number of books bought = }8\\\text{or, }x+y=8\\\text{or, }y=8-x...........(1)$

$\text{Now, }$

$\text{Cost of 1 math book = }\ 29.60\\\therefore\ \text{Cost of }x\text{ math books = }\ 29.6x\\\\\text{Also, cost of 1 english book = }\ 29.90\\\therefore\ \text{Cost of }y\text{ english books = }\ 29.9y$

$\text{According to the question, he bought }x\text{ math books and }y\text{ english books for }\\\ 238.6.\\\therefore\ \text{Total money spent = Cost of }x\text{ math books }+\text{Cost of }y\text{ english books}\\\text{or, }238.6=29.6x+29.9y\\\text{From equation(1),}\\\text{}\hspace{0.5cm}238.6=29.6x+29.9(8-x)\\\text{or, }238.6=29.6x+239.2-29.9x\\\text{or, }238.6-239.2=29.6x-29.9x\\\text{or, }-0.6=-0.3x\\\text{or, }x=2$

$\text{Equation(1) becomes, }\\y=8-2=6$

$\text{So he bought 2 math books and 6 english books.}$