Of the 100 employees at a company, 75 are married and 57 have at least one child. 33 of the employees married do not have any children. If an employee is chosen at random, find the probability that an employee has at least one child given that they are married.

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Answer:

0.76

Step-by-step explanation:

To find the probability that an employee has at least one child given that they are married, we can use the concept of conditional probability.

Given information:

- Total number of employees = 100

- Number of married employees = 75

- Number of employees with at least one child = 57

- Number of married employees without children = 33

1. Find the probability that an employee has at least one child and is married:

\[ P(\text{Married and at least one child}) = \frac{57}{100} \]

2. Find the probability that an employee is married:

\[ P(\text{Married}) = \frac{75}{100} \]

3. Find the probability that an employee is married and has at least one child:

\[ P(\text{Married and at least one child}) = \frac{57}{100} \]

4. Find the probability that an employee has at least one child given that they are married using the formula for conditional probability:

\[ P(\text{At least one child | Married}) = \frac{P(\text{Married and at least one child})}{P(\text{Married})} \]

5. Substitute the values:

\[ P(\text{At least one child | Married}) = \frac{57/100}{75/100} \]

\[ P(\text{At least one child | Married}) = \frac{57}{75} = \frac{19}{25} \]

Therefore, the probability that an employee has at least one child given that they are married is \( \frac{19}{25} \) or 0.76.

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