remember
if no base is stated, assume base 10
and
[tex]log_a(b)=c[/tex] translates to [tex]a^c=b[/tex]
and
[tex]log(a)+log(b)=log(ab)[/tex]
and
[tex]log(a)-log(b)=log(\frac{a}{b})[/tex]
and
[tex](r)log(x)=log(x^r)[/tex]
so
minus log3 from both sides
2log(x)-2log(3)=0
translate
[tex]log(x^2)-log(3^2)=0[/tex]
translate
[tex]log(\frac{x^2}{9})=0[/tex]
translate
[tex]10^0=\frac{x^2}{9}[/tex]
[tex]1=\frac{x^2}{9}[/tex]
times both side by 9
9=x²
+/-3=x
x=-3 or 3
