Question

A local hamburger shop sold a combined total of 390 hamburgers and cheeseburgers on Saturday there were 60 fewer cheeseburgers sold than hamburgers how many hamburgers were sold on Saturday

Answer 1

Answer:

225

Step-by-step explanation:

Let's denote the number of hamburgers sold as H

and the number of cheeseburgers sold as C

We're given that the total number of hamburgers and cheeseburgers sold is 390:

H+C=190

We're also told that there were 60 fewer cheeseburgers sold than hamburgers:

C=H−60

Now, we can substitute the expression for

C

from the second equation into the first equation:

H+(H−60)=390

Solving for

H

2H−60=390

2H=390+60

2H=450

H= 450/2

H=225

So, 225 hamburgers were sold on Saturday.

Answer 2

Answer:

225 hamburgers

Step-by-step explanation:

Let's define our variables:

• $\sf x$ = number of hamburgers sold
• $\sf y$ = number of cheeseburgers sold

Given that a combined total of 390 hamburgers and cheeseburgers were sold, we have the equation:

$\sf x + y = 390$

Also, it's given that there were 60 fewer cheeseburgers sold than hamburgers:

$\sf y = x - 60$

Now we can solve this system of equations. Substituting the second equation into the first:

$\sf x + (x - 60) = 390$

$\sf 2x - 60 = 390$

Adding 60 to both sides:

$\sf 2x - 60 +60= 390+60$

$\sf 2x = 450$

Dividing both sides by 2:

$\sf \dfrac{2x}{2}=\dfrac{450}{2}$

$\sf x = 225$

So, 225 hamburgers were sold on Saturday.