Question

Who do I solve this? Please help!

Answer 1

Answer:

$g(1) = \boxed{1}$

Step-by-step explanation:

The given function g(x), is a piecewise function which has different definitions for different x intervals

We are asked to find the value of g at x = 1 i.e. g(1)

Note that when x is not equal to either -2 or -1, the function definition is
$g(x) = x^3 - x^2 + 1$

Since $x = 1$  follows the property $x \ne -2, -1$  the correct definition to use is
$g(x) = x^3 - x^2 + 1$

Therefore
$g(1) = 1^3 - 1^2 + 1$
$g(1) = 1 - 1 + 1$
$g(1) = \boxed{1}$