Answer:
To find the resulting boiling point of the solution, you can use the equation:
ΔT = i * Kb * m
Where:
- ΔT is the change in boiling point,
- i is the van't Hoff factor,
- Kb is the ebullioscopic constant of the solvent (water),
- and m is the molality of the solution.
For calcium chloride (CaCl2), it dissociates into three ions in solution (1 Ca²⁺ ion and 2 Cl⁻ ions), so the van't Hoff factor (i) is 3.
Given:
- Kb for water = 0.51°C/m
- Molality (m) = 3.9 m
- i = 3
Plug these values into the equation:
ΔT = 3 * 0.51°C/m * 3.9 m
ΔT = 5.67°C
So, the resulting boiling point of the solution is 100°C + 5.67°C = 105.67°C.
