The distance between any 2 points P(a,b) and
Q(c,d) in the coordinate plane, is given by the formula:
[tex]|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}
}[/tex]
Thus the distance between points t(13, 1.6) and v(5.4, 3.7) is found using the formula as:
[tex]|tv|= \sqrt{(13-5.4)^{2} + (1.6-3.7)^{2}}= \sqrt{ (7.6)^{2}+ (-2.1)^{2}}=\\\\ \sqrt{57.76+4.41}= \sqrt{62.17} \approx 7.9 [/tex]
Answer: 7.9
