Question

Why is the acceleration not 9.8 /I thought this was a projectile motion It’s this question ; ; A jet plane is launched from a catapult on an aircraft carrier. In 2.0 s it reaches a speed of 42 m/s at the end of the catapult. Assuming the acceleration is constant, how far did it travel during those 2.0 s?

Answer 1

Answer:

42 meters.

Explanation:

You use the formula for uniform acceleration: x=1/2at^2 and velocity : v=at

v=at

42=a2

a=21m/s^2

x=1/2(21)(2^2)

x=42m traveled

9.8m/s^2 acceleration is only for free fall projectile motion questions, where there is a y component. This equation is only horizontal, and thus the only accleration is horizontal.