Question

4. The area of a playground is 50 square yards. The length of the playground is 2 times longer than its width. Find the
length and width of the playground.
a. length 10 yd, width = 5 yd
b. length 5 yd, width = 10 yd
c. length = 2.5 yd, width = 20 yd
d. length 20 yd, width = 2.5 yd

Answer 1

Answer:

a. length 10 yd, width = 5 yd

Step-by-step explanation:

We know that the length is 2 times the width

l = 2w

The area is

A = l*w = (2w) * w = 2w^2

and the area is 50 yd^2

50 = 2w^2

Divide each side by 2.

50/2 = 2w^2 /2

25 = w^2

Take the square root of each side.

sqrt(25) = sqrt(w^2)

5 =w

The width is 5 yds

length = 2*w = 2*5 = 10 yds