What two rational expressions sum to 3x−4/x^2+x−12?
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Answer:
3x / (x - 3)(x + 4) + (-4) / (x - 3)(x + 4)
Step-by-step explanation:
3x - 4 / x² + x - 12
= 3x - 4 / x² + 4x - 3x - 12
= 3x - 4 / x(x + 4) -3(x + 4)
= 3x - 4 / (x + 4)(x - 3)
thus,
the required expression is:
3x / (x + 4)(x - 3) + (-4) / (x + 4)(x - 3)