The answer to this question is:
I have 3 pieces of candy to place in 4 lunch boxes. In how many ways can I do this if: (a) The candies are all the same and the lunch boxes are all different? (b) The candies are all different and the lunch boxes are all the same? (c) Exactly two of the candies are the same (but the third is different) and all of the lunch boxes are different? Please explain your work IN DETAIL. Thanks!?.
A).4^3 = 64
B).(3+4-1)C3 = 6c3 = 20
C).3c3 +3c2 + 3c1 = 7
The last Question). 4!/2! ways = 4+24+12 = 40 ways
Hoped This Helped,
Alialbaghdadi6
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