Question

Which trigonometric ratios are correct for triangle ABC? Check all that apply

Answer 1

The correct answer on Edgeniuty is:
A)  Sin (C)
C)  Tan (C)
D)  Sin (B)

Answer 2

Answer: $\sin C=\sin(60^{\circ})=\frac{\sqrt{3}}{2}$

$\tan C=\tan(60^{\circ})=\sqrt{3}$

$\sin B=\sin(30^{\circ})=\frac{1}{2}$

Step-by-step explanation:

In the given triangle ABC

∠A = 90°

∠B= 30°

∠C= 60°

AC=9

BC=18

By using trigonometric function values for the given angles, we have

The value of $\sin C=\sin(60^{\circ})=\frac{\sqrt{3}}{2}$

The value of $\cos B=\cos(30^{\circ})=\frac{\sqrt{3}}{2}\neq\frac{\sqrt{2}}{3}$

The value of $\tan C=\tan(60^{\circ})=\sqrt{3}$

The value of $\sin B=\sin(30^{\circ})=\frac{1}{2}$

The value of $\tan B=\tan(30^{\circ})=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}\neq\frac{2\sqrt{3}}{3}$