Question

what is the midpoint coordinates of segment HX H(13,8) X(-6,-6)

Answer 1

midpoint of (x1,y1) and (x2,y2) is

$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is

$(\frac{13-6}{2},\frac{8-6}{2}=$
$(\frac{7}{2},\frac{2}{2}=$
$(3.5,1)$

the midpoint is (3.5,1)