Question

A flat rectangular piece of aluminum has a perimeter of 70 inches. The length is 11 inches longer than the width. Find the width. A. 34 inches B. 35 inches C. 23 inches D. 12 inches

Answer 1

perimeter = 2L +2w

L = w+11

70 = 2(w+11) +2w

70 = 2w+22+2w

70= 4w + 22

48 = 4w

w=48/4 = 12

width = 12

length = 12+11 = 23

2x12 = 24

2x23 = 46

46+24 = 40

 length = 23 inches, width = 12 inches

Answer is D

Answer 2

Answer:

The answer is the option D

$12\ inches$

Step-by-step explanation:

we know that

The perimeter of a rectangle is equal to

$P=2L+2W$

where

L is the length side of the rectangle

W is the width side of the rectangle

In this problem we have

$P=70\ in$

so

$70=2L+2W$ ------> equation A

$L=W+11$ ------> equation B

Substitute equation B in equation A and solve for W

$70=2[W+11]+2W$

$70=2W+22+2W$

$4W=70-22$

$W=48/4$

$W=12\ in$