Respuesta :
The plane's velocity of 35.11 m/s is actually due in a north-eastward direction. The 12 m/s velocity is the vertical component of the plane's velocity, hence it is pointing northwards. We will use the formula:
Vy = Vsin∅
To determine the angle ∅ at which the plane is flying. This is:
12 = 35.11 * sin∅
∅ = 20.0 degrees
The eastward velocity is:
Vx = Vcos∅
Vx = 35.11 * cos(20)
Vx = 33.0 m/s
The plane's eastward velocity is 33.0 m/s
Vy = Vsin∅
To determine the angle ∅ at which the plane is flying. This is:
12 = 35.11 * sin∅
∅ = 20.0 degrees
The eastward velocity is:
Vx = Vcos∅
Vx = 35.11 * cos(20)
Vx = 33.0 m/s
The plane's eastward velocity is 33.0 m/s
The question says: The airplane flew due north for the given duration (i interpret m/s to be milliseconds) and at the given velocity.
The statement mentions no change in direction or angle, therefore the airplane does not fly east (or the airplane travels 0.0m east).
The statement mentions no change in direction or angle, therefore the airplane does not fly east (or the airplane travels 0.0m east).